There is a prison with 100 prisoners, each in separate cells, which are sealed off, soundproof and windowless. There is a lobby in the prison with a lightbulb in it. Each day, the warden will pick one of the prisoners at random (even if they have been picked before) and take them out to the lobby. The prisoner will have the choice to flip the lightbulb switch if they want. The lightbulb starts in the "off" position.

When a prisoner is brought out to the lobby, he also has the option of saying "Every other prisoner has been brought out to the lobby." If a prisoner chooses to say this and it is true, all the prisoners will go free. However, if a prisoner chooses to say this and it's wrong, all the prisoners will be executed. So a prisoner should only say this if he knows it is true for sure.

Before the first day of this process begins, all the prisoners are allowed to get together to discuss a strategy to eventually save themselves.

What strategy could they use to ensure their eventual salvation?

idk how do u find all of these riddles

GOOGLE.COM

Stop ruining the fun by looking them up!!!!!!!!!!!!

They determine how many flips of the switch between on and off for 100 prisoners.
There are two options, and 100 prisoners, so therefore using math we
do 100prisoners x 2lightswitch options.
After 200 switches between "Off" and "On" they will know how many have gone.
However, since they are picked at random they can ask the Warden to close his eyes and pretend to flip the switch, thus detering confusion. After all, this IS a riddle so think outside the box.

Or every prisoner that goes to the lobby can mark blood on their doors if they have been called on. So the very last prisoner walks to the lobby he can look at all their doors and determine if they have all been called on. Although if one of them have not been called on he has to wait for his next turn to see if those individuals have been called on. Only the last prisoner can do it because he is at the end so that gives him an advantage to look at everybody's door.
the prisoners mark blood on the outside part of the door.

No and no. Keep trying!

2 words


killing themselves

no

now ur wrong

I Made the riddle!

So you have the correct answer. Although your not thinking logical so your answer is invalid and, our answers are correct.

no i know the answer and all im asking is for somebody to guess it!

I think if they brake the bars open and get awawy

NOPE!!

idk xD

GOOGLE.COM

1. Appoint a "scorekeeper" and the other 99 prisoners as "transmitters".

2. When a transmitter enter the switch room for the first time, he will flick switch B ON if he sees it in the OFF position. Alternatively, he will flick switch A if he sees switch B is in the ON position and waits for his next visit. The transmitter's mission is to find ONE opportunity to flick switch B to the ON position. After he completes his mission, he will flick switch A for all subsequent visits. In short, each transmitter's role is to send a signal to the scorekeeper that he has been to the switch room.

3. The scorekeeper's role is to flick off switch B whenever he sees it in the ON position. Each time he flicks off switch B he adds 1 to his score. When he sees switch B is already OFF, he flicks switch A instead and does not add to the score. As soon as he accumulates 100, he reports to the Warden.

I have another solution

One prisoner is designated as the "caller." He and only he will make the determination of when everyone's been in the room. Whenever he sees that the left-hand switch is "down," he will move it "up" and add 1 to his count; otherwise, he will flip the right-hand switch and not think anything of it. When the other prisoners enter the room, they have a different strategy. If the left-hand switch is "up," they will switch it "down," but they will only do this the first two times they encounter the left-hand switch "up." If they've moved the left switch twice already, or if the left-hand switch is "down," they will flip the right-hand switch.

When the caller's count is twice the number of prisoners plus one, each prisoner must have been in the room at least once, regardless of the initial configuration of the switches.

The answer is:
Make one of the prisoners the "lead" prisoner. This prisoner is the ONLY one who is allowed to turn the light off.

Each time any of the other prisoners goes into the lobby, if the light is off, they will turn the light on, but only if they've never turned it on before. This means that each prisoner will only ever turn the light on once.

Meanwhile, every time the lead prisoner goes into the lobby, he will turn the light off if it's on. He will keep track of the number of times he has turned the light off.

Once the lead prisoner turns off the light for the 99th time, he knows that every other prisoner has turned the light on once (and thus has been in the lobby). At this point, he may say that all the prisoners have been to the lobby, and they will all go free.

Look out 4 #9!!!!!!!

if that guard dude picks ONE prisoner to go to the lobby than how would the lead be out in the lobby? plus if you got this on google than u didnt make it.google isnt always right.ur answer might be wrong while the answer is,"when in the lobby,run for your life" suc.k it